$acmeshell: supply filename in $0

[marius.eriksen, 2012-11-26 03:42:21]

After using $acmeshell for a while, I was really beginning to miss $%, which
isn't accessible in bash since % is job substitution in bourne shells.

I think supplying the filename as argv[0] is both natural and makes sense: you
are executing the snippet within the context of the file, so in a sense it is
argv[0].

[rsc, 2012-11-26 03:47:41]

Making it argv[0] does not make sense to me. The file is not what is
being executed. I would suggest making the file name available under a
different variable. $samfile would be a good, if slightly misnamed,
choice, because the file is already available under that name when
using sam's ! command. That is, where there is currently a putenv for
"%", add one for "samfile" too.

Russ

[rsc, 2012-11-26 03:54:26]

LGTM

[marius.eriksen, 2012-11-26 03:55:24]

I can live with that. It also has the major advantage of being passed through in
environments, so you can write scripts that are invoked with button-2 without
inspecting the acme environment through $winid (the file often being the only
thing you care about anyway).

[rsc, 2012-11-26 03:56:46]

*** Submitted as http://code.google.com/p/plan9port/source/detail?r=27ec22f7be57
***

acme: set $samfile (same as $%) during execution

R=rsc
CC=plan9port.codebot
http://codereview.appspot.com/6854092

Committer: Russ Cox <rsc@swtch.com>