Issue 26052: Hashing protocol for dtypes

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Issue 26052: Hashing protocol for dtypes (Closed)

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Created:
15 years, 1 month ago by cournape

Modified:
14 years, 8 months ago

Reviewers:
stefanv

Base URL:
http://svn.python.org/view/*checkout*/python/trunk/

Visibility:
Public.

Description

First shot - seems to work for simple compound, subarray and builtin dtypes

Patch Set 1 #

Created: 15 years, 1 month ago

Download [raw] [tar.bz2]

Unified diffs	Side-by-side diffs	Stats (+356 lines, -1 line)			Patch
numpy/core/setup.py	View	1 chunk	+1 line, -0 lines	0 comments	Download
numpy/core/src/hashdescr.c	View	1 chunk	+287 lines, -0 lines	0 comments	Download
numpy/core/src/multiarraymodule.c	View	2 chunks	+2 lines, -1 line	0 comments	Download
numpy/core/tests/test_dtype.py	View	1 chunk	+66 lines, -0 lines	0 comments	Download

Messages

Total messages: 4

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stefanv

In [20]: hash(np.dtype([('t', float),('y', float)])) == hash(np.dtype([('x', float), ('y', float)])) Out[20]: True But In [3]: ...

15 years, 1 month ago (2009-03-13 16:03:39 UTC) #2

stefanv

In [34]: hash(np.dtype([('f2', [('f2', np.int16)])])) Out[34]: 148882832 In [35]: hash(np.dtype([('f1', [('f2', np.int16)])])) Out[35]: 148882832

15 years, 1 month ago (2009-03-13 17:02:57 UTC) #3

stefanv

15 years, 1 month ago (2009-03-13 17:03:19 UTC) #4

On 2009/03/13 16:03:39, Stefan wrote:
> In [20]: hash(np.dtype([('t', float),('y', float)])) == hash(np.dtype([('x',
> float), ('y', float)]))
> Out[20]: True
> 
> But
> 
> In [3]: a,b = np.dtype([('t', float),('y', float)]), np.dtype([('x', float),
> ('y', float)])
> In [7]: hash(a) == hash(b)
> Out[7]: False
> 
> I must be doing something silly.  Do you know what?

Clean build fixed this issue.

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